cos 2x /sin^2 x*cos^2 x不定积分
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cos 2x /sin^2 x*cos^2 x不定积分
答案是“-tanx-cotx+c"我要过程....
答案是“-tanx-cotx+c"我要过程....
∫cos2xdx/(sin^2xcos^2x)
= 4∫cos2xdx/(2sinxcosx)^2
=4 ∫cos2xdx/(sin2x)^2
=2 ∫cos2xd(2x)/(sin2x)^2
=2 ∫d(sin2x)/(sin2x)^2
=-2*1/(sin2x)+c
=-2csc2x+c.
再问: 答案是“-tanx-cotx+c"我要过程....拜托您了
再答: 因为-tanx-cotx=-(sinx/cosx+cosx/sinx)=-(sin^2x+cos^2x)/sinxcosx=-1/sinxcosx=-2/sin2x=-2csc2x. 或者采取如下积分: ∫cos 2x dx/sin^2 x*cos^2 x =∫(2cos^2x-1)dx/sin^2x*cos^2x =∫(cos^2 x-sin^2 x)dx/(sin^2 x*cos^2 x) = ∫(1/sin^2 X-1/cos^2 x)dx =∫dx/sin^2x-∫dx/cos^2x = ∫csc^2xdx-∫sec^2xdx =-cotx-tanx+c.
= 4∫cos2xdx/(2sinxcosx)^2
=4 ∫cos2xdx/(sin2x)^2
=2 ∫cos2xd(2x)/(sin2x)^2
=2 ∫d(sin2x)/(sin2x)^2
=-2*1/(sin2x)+c
=-2csc2x+c.
再问: 答案是“-tanx-cotx+c"我要过程....拜托您了
再答: 因为-tanx-cotx=-(sinx/cosx+cosx/sinx)=-(sin^2x+cos^2x)/sinxcosx=-1/sinxcosx=-2/sin2x=-2csc2x. 或者采取如下积分: ∫cos 2x dx/sin^2 x*cos^2 x =∫(2cos^2x-1)dx/sin^2x*cos^2x =∫(cos^2 x-sin^2 x)dx/(sin^2 x*cos^2 x) = ∫(1/sin^2 X-1/cos^2 x)dx =∫dx/sin^2x-∫dx/cos^2x = ∫csc^2xdx-∫sec^2xdx =-cotx-tanx+c.
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