化简(x²-2xy+y²-1)/x-y-1=? 写上过程! 谢!
化简(x²-2xy+y²-1)/x-y-1=? 写上过程! 谢!
已知(4X-2Y-1)²+根号xy-2=0,求4x²y²+xy²的值
3y/2x+2y+2xy/x²+xy 2x/x²-64y²-1/x-8y (1/a+1/b
已知x+y=7,xy=2,求:(1)2x²+2y²的值;(2)(x-y)²的值
1-x²+2xy-y²
已知 (x+1)² +|y-1|=0,求 2(xy-xy²)-(3xy²-xy) 的值.
一道方程组(要过程)X²+3XY+Y²+2Y=8 2X²+2Y²+3X+3Y=1
计算:(1).(-2xy²)*(3x²y)²
已知x²+y²=3xy且xy≠0,求x²y-²+x-²y²的
问已知x²+y²=7,xy=-2,求5x²-3xy-4y²-11xy-7x&su
已知x,y满足x²+y²-4x-6y+13=0,求(-y/x³)³÷(-1/xy
(3x+2y)(9x²-6xy+4y²﹚