An object thrown straight up falls back and is caught at the

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An object thrown straight up falls back and is caught at the same place it is launched from.Its time of flight is T; its maximum height is H.Neglect air resistance.What is its average velocity for the second half of the trip?(Use any variable or symbol stated above as necessary.)
一物体从原点竖直向上抛出然后落回原点。总共运动时间是T，达到的最大高度是H。忽略空气阻力。问后半程的平均速度是多少？（请使用上文提到的变量和符号来表示）

V=H/2T,因为是竖直上抛运动,前半程和后后半程具有等时性.又因为平均速度等于位移除以时间.所以答案就是H/2T
再问：不对啊。。。

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