作业帮证明2sin(60°+α)cos(60°-α)=√3/2+sin2α,麻烦写下具体步骤.
来源：学生作业帮 编辑：拍题作业网作业帮 分类：数学作业 时间：2024/04/28 02:44:05
证明2sin(60°+α)cos(60°-α)=√3/2+sin2α,麻烦写下具体步骤.
左边=sin(60°+α)cos(60°-α)+sin(60°+α)cos(60°-α)
=[sin(60°+α)cos(60°-α)+cos(60°+α)sin(60°-α)]+[sin(60°+α)cos(60°-α)-cos(60°+α)sin(60°-α)]
=sin[(60°+α)+(60°-α)]+sin[(60°+α)-(60°-α)]
=sin120°+sin2α
=√3/2+sin2α
=右边 .
=[sin(60°+α)cos(60°-α)+cos(60°+α)sin(60°-α)]+[sin(60°+α)cos(60°-α)-cos(60°+α)sin(60°-α)]
=sin[(60°+α)+(60°-α)]+sin[(60°+α)-(60°-α)]
=sin120°+sin2α
=√3/2+sin2α
=右边 .
证明2sin(60°+α)cos(60°-α)=√3/2+sin2α,麻烦写下具体步骤.
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