matlab基础 x=0:0.1:2*pi;y1=sin(x);y2=cos(x);z=[y1,y2];plot(x,z
matlab基础 x=0:0.1:2*pi;y1=sin(x);y2=cos(x);z=[y1,y2];plot(x,z
用MATLAB画图,例>> x=0:pi/15:2*pi; >> y1=sin(x); >> y2=cos(x); >>
利用 plot 函数在一个坐标系下绘制以下函数的图形,y1=sin(x) ; y2=cos(x) ; y3=cos(2x
程序如下:x=linspace(0,4*pi,100);y1=sin(x);y2=cos(x);y3=sin(x)./(
matlab2009中运行 :x=0:0.01:2*pi; y=sin(x); y2=cos(x); z=[y;y2];
用MATLAB编写代码:画y1=sin(2x)和y2=cos(2x)在区间[0,4*pi]的曲线,用+标出两条曲线的交点
用MATLAB编写代码:绘制y1=sin(2x)和y2=cos(2x)在区间[0,4*pi]的曲线,用加号标出两条曲线的
1.已知y1=-x+2,y2=3x+4,当x分别取何值时,y1=y2,y1<y2,y1>y2?
matlab中 x=[0:0.15:2*pi]; y=[0:0.15:2*pi]; z=sin(y‘)*cos(x);
一次函数y1=2x+1,y2=5x+16,当x分别取何值时,y1=y2,y1>y2,y1
x=-pi:0.1:pi; fh={@cos,@sin}; plot(fh{2}(x)) 刚学习matlab,谁帮我解释
matlab中,已知y1=f(x),y2=g(x),如何画出y1关于y2的函数图像