SAT2数学题一道,if a square prism is inscribed in a right circular
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SAT2数学题一道,
if a square prism is inscribed in a right circular cylinder of radius 3 and height 6,the volume inside the cylinder but outside the prism is,我知道答案是61.6,请发下详细解答过程
if a square prism is inscribed in a right circular cylinder of radius 3 and height 6,the volume inside the cylinder but outside the prism is,我知道答案是61.6,请发下详细解答过程
先看一下题意:
正方体棱柱内切于一个圆柱内.也就是说棱柱的底面是正方形,正方形内切于圆柱.知道圆柱底面的半径是3,圆柱高为6.隐含意思就是棱柱的高为6.而题意的意思其实就是要你算出圆柱体内,除了棱柱的体积,剩下的体积是多少?也就是圆柱体的体积减去棱柱的体积.
了解了题目,就可以直接解答了.
先求圆柱体的体积,很简单,底面积乘以高.3.14乘以3的平方,再乘以6.结果是169.56.
再求棱柱的体积.底面积乘以高.高为已知隐含条件6.底面积是正方形,只需求出边长.画个图形,正方形内切于圆.已知圆的半径为3,很容易求出正方形的边长为3√2.底面积也就是18.棱柱体积为:18*6=108.
差积为:169.56-108=61.56.即你说的61.6.
正方体棱柱内切于一个圆柱内.也就是说棱柱的底面是正方形,正方形内切于圆柱.知道圆柱底面的半径是3,圆柱高为6.隐含意思就是棱柱的高为6.而题意的意思其实就是要你算出圆柱体内,除了棱柱的体积,剩下的体积是多少?也就是圆柱体的体积减去棱柱的体积.
了解了题目,就可以直接解答了.
先求圆柱体的体积,很简单,底面积乘以高.3.14乘以3的平方,再乘以6.结果是169.56.
再求棱柱的体积.底面积乘以高.高为已知隐含条件6.底面积是正方形,只需求出边长.画个图形,正方形内切于圆.已知圆的半径为3,很容易求出正方形的边长为3√2.底面积也就是18.棱柱体积为:18*6=108.
差积为:169.56-108=61.56.即你说的61.6.
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