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Maya is 6 km offshore on a boat at point B and wishes to rea

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Maya is 6 km offshore on a boat at point B and wishes to reach a coastal village
which is 4 km down the straight shoreline at point D from the point A on the shore
nearest to the boat.
说,maya在距离海岸6km的船上此点记做b点,她想要到大距离船最近的海岸a点沿着海岸线向下4km的村庄记做d点,我翻译的把我给绕进去了!压根没明白这几个点的位置关系..T T
She can row at 5 km/hour and run 7 km/hour.
她划船的速度是5 km/h 跑步的速度是7km/h
Point C is where she should land her boat to reach the village in the least amount of time.C点呢是她可以泊船的地方(船停在海边),这个点距离他要去的村庄最近,
a) Draw a labeled diagram for this problem,which includes points A,B,C,and D.
Let x be the distance between points A and C.
我觉得我理解的有问题.abcd4个点分别是不是有3个围城了一个直角三角形?.大概描述一下他们的位置.
b) What two assumptions should you make about the wind and the water?
水和风是什么假设关系?
c) State the following quantities:
running distance = ___?她跑了多米?running time =___?跑了多长时间?
rowing distance = ___?她划船花了有多少米?rowing time =___?她划船划了多长时间?
d) How far away is point C from point A accurate to 2 decimal places?
c点道a点有多远?
应用题我老读题理解错题目意思..
有错的地方请指教..
b点是船的原始点
a点是她停靠的点(距离她的船最近)
c点是道村庄最近的点
d点是村庄。
你理解错了,A是B到岸边的垂足,长6;AD为海岸线,长4,C点为他选择的停靠点,在AD线上.
题目就是要你给出风速和水速的关系,以此算出C点,使到达目标用时最短
再问: 哪请问c呢?????? 我画的是a是b的垂足吧?长6。 ac才是海岸线吧?? 如果再一条线上底下的那几问怎么求呢??
再答: C是要算的,如果不考虑风速和水速,总时间= BC/船速 +CD/步行速度,是一个关于X的函数。求X使时间最小 根号下(6^2+x^2) /5 +(4-x)/7 最小时,x=2.5× 根号6