八年级下册数学题(1)a²-(x²+2x+1)(2)(y+1)²-9(y-1)²
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八年级下册数学题
(1)a²-(x²+2x+1)(2)(y+1)²-9(y-1)²(3)(x²-2x)²+2(x²-2x)+1
(4)(x²+4)²-16x²(5)a²-8a²b²+16b四次方(6)(3x+y)(2x-3y)-3x(3x+y)
要过程 谢谢了
现在只要1,2,6题 其他不用了
(1)a²-(x²+2x+1)(2)(y+1)²-9(y-1)²(3)(x²-2x)²+2(x²-2x)+1
(4)(x²+4)²-16x²(5)a²-8a²b²+16b四次方(6)(3x+y)(2x-3y)-3x(3x+y)
要过程 谢谢了
现在只要1,2,6题 其他不用了
a²-(x²+2x+1)=a²-(x+1)²=(a+x+1)(a-x-1)
(2)(y+1)²-9(y-1)²=(y+1+3(y-1))(y+1-3(y-1))=(4y-2)(4-2y)
(3)(x²-2x)²+2(x²-2x)+1=(x²-2x+1)²=(x-1)^4
(4)(x²+4)²-16x²=(x²+4-4x)(x²+4+4x)=(x+2)²(x-2)²
(5)a²-8a²b²+16b四次方=?
(6)(3x+y)(2x-3y)-3x(3x+y)=6x²+2xy-9xy-3y²-9x²-3xy=-3x²-3y²-10xy=-(x+3y)(3x+y)
第五题是不是a^4-8a²b²+16b^4=(a²-4b²)²
(2)(y+1)²-9(y-1)²=(y+1+3(y-1))(y+1-3(y-1))=(4y-2)(4-2y)
(3)(x²-2x)²+2(x²-2x)+1=(x²-2x+1)²=(x-1)^4
(4)(x²+4)²-16x²=(x²+4-4x)(x²+4+4x)=(x+2)²(x-2)²
(5)a²-8a²b²+16b四次方=?
(6)(3x+y)(2x-3y)-3x(3x+y)=6x²+2xy-9xy-3y²-9x²-3xy=-3x²-3y²-10xy=-(x+3y)(3x+y)
第五题是不是a^4-8a²b²+16b^4=(a²-4b²)²
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