| (5+b)
根据题意得:
a−3=0 5+b=0 c−1=0, 解得:
a=3 b=−5 c=1, 则原式= −5−1 3=-2.
若a、b、c满足|a−3|+(5+b)
a,b,c满足5c-3a
已知正整数a,b,c满足:5c-3a
设实数a,b,c满足a+b=6−4a+3a
若a,b,c满足不等式b+c>a,且(a-b-c)x
已知实数a、b、c满足等式a−2+|b+1|+(c+a−b)
若实数a,b,c满足a-3的绝对值+(5+b)的平方+根号下c+7=0,求代数式a/b+c的值
若a,b,c满足ㄧa-3ㄧ+根号(5+b)的平方+根号c-1=0,求代数式a分之b-c的值
若a,b,c,d都是自然数,且满足a^5+b^4,c^3+d^2,且c-a=19,求d-b的值
若a,b,c满足a/2=b/3=c/4,求1/a-1/b的值
已知三个未知数A,B,C满足3A+2B+C=5和2A+B
若a、b、c满足2a=3b=4c,求分式3a+2b-c/a-2b+3c的值
|