cos2x+sin2x=1 那么sinx-cosx等于多少
cos2x+sin2x=1 那么sinx-cosx等于多少
(sinx^2+sin2x)/(cosx^2=cos2x)等于多少
如果f(sinx)=cos2x,那么f(cosx)等于 A.-sin2x B.sin2x C.-cos2x D.cos2
怎么证明cos2x/1-sin2x = cosx+sinx/cosx-sinx
若f(sinx)=cos2x,那么f(cosx)等于多少?
求证:(1-2sinx×cosx)/cos2x-sin2x=(cos2x-sin2x)/(1+2sinx×cosx)
若3SinX=CosX,则Cos2X+Sin2X等于?
sinx×cos2x-sin2x×cosx
已知sinx=-1/2cosx,cosx-sinx/cosx+sinx+sin2x+cos2x的值
Cosx+sinx分之1+sin2x+cos2x=2cos 证明
已知1+sinx+cosx+sin2x+cos2x=0,求tanx
求证sinx+sin3x+sin2x=1+cos2x+cosx