设全集U={-3,-2,-1,0,1,2,3},M={-3,-2,-1,0},N={0,1,2,3},则集合(CuM)∩
设全集U={-3,-2,-1,0,1,2,3},M={-3,-2,-1,0},N={0,1,2,3},则集合(CuM)∩
1 已知全集u{1,2,3,4,5,6},集合m={1,3,5},n={2,4,6},则CuM∩N=N,为什么?
若全集U={1,2,3,4,5,6},M={2,3},N={1,4},则集合N∩(CuM)等于( )
设集合M={y│-1≤y≤2},N={y│y≥0}全集U=R,求(CuM)交(CuN).
设全集U=坐标的形式,X,Y都属于实数,集合M的X,Y满足y-3/x-2=1,N中X,Y满足x-3=x-2那么CuM∩N
设全集U=R,M={x|x方-2x-3<等于0},N={1-x<0}求M交N,M并N,CuM
已知全集u=R,集合M={x,|x-2|≥3},则CuM=
设全集U={0,1,2,3},集合M={0,1,2},集合N={0,2,3},则M∪(CUN)=( )
设全集U=R,集合M={x/x≥2},N={y/y>0},则CuM与CuN的包含关系是
已知全集U={1,2,3,4,5},M∩N={5},Cu(M∩N)={4},CuM∩CuN={1,2}
设全集U={0,1,2,3},集合M={0,1,2},N={0,2,3},则M∩CuN=( )
1.设全集U=R.M={m|方程mx^2-x-1=0有实数根}N={n|方程x^2-x+n=0有实数根},求(CuM)∩