a√(a/b)÷√ab×√(1/ab)(b>0)
a√(a/b)÷√ab×√(1/ab)(b>0)
化简[√ab-ab/(a+√ab)]÷(√ab-a)/(a-b)
已知a大于0,b大于0,且2√a(√a+2√b)=√b(√a+5√b),求(2a+√ab+3b)÷(3a+√ab-2b)
(√a+√a+√b分之b-√ab)除以(√ab+b分之a+√ab-a分之b-√ab分之a+b)(a≠ b)
已知ab≠0,且实数a、b满足√a(√a+√b)=3√b(2/3√a+4√b),那么(a-5b+√ab)/(a+b+√a
已知√a-1+(ab-2)^2=0,求1/ab+1/(a+1)(b+1)+1/(a+2)(b+2)+.+1/(a+200
化简a+b/(√a+√b)+2ab/(a√b+b√a)
(a-b/根号a-根号b)-(a+b-2√ ab/√ a-√b) 求速解 3Q
a,b属于R,a>0,b>0是((a+b)/2)>√(ab)的什么条件
[√a+(b-√ab)/(√a+√b)]/[a/(√ab+b)+b/(√ab-a)-(a+b)/√ab]=
已知a>b>0,求证:(a-b)^2/8a < (a+b)/2 -√ab < (a-b)^2/8b
已知√a-1+(ab-2)²=0,求a+4b的平方根