(2013•南充二模)将函数f(x)=sin(2x+
(2013•南充二模)将函数f(x)=sin(2x+
(2013•南充二模)将函数f(x)=sin(2x+π6)的图象向右平移π6个单位,那么所得的图象对应的函数解析式是(
(2013•盐城二模)函数f(x)=2sin(x−π4)
(2013•潮州二模)已知函数f(x)=sin(2x+π3)
(2010•东城区二模)已知函数f(x)=sinωx,g(x)=sin(2x+π2),有下列命题:
(2013•青岛二模)已知函数f(x)=sin(2x+π6)−2cos2x.
(2013•昌平区二模)已知函数f(x)=sin(π-2x)+23cos2x,x∈R.
(2013•昌平区二模)已知函数f(x)=3sin(π−2x)-2cos2x+1,x∈R.
(2013•临沂二模)已知x∈R,ω>0,u=(1,sin(ωx+π2)),v=(cos2ωx,3sinωx)函数f(x
(2011•绵阳二模)已知函数f(x)=sin x-cos (x-π6
(2012•杭州二模)函数f(x)=sin(x+π2)cosx(x+π6)
(2014•辽宁二模)函数f(x)=log0.5[sin(π3