已知m/n = 5/3 求m/(m+n)+m/(m-n)-n^2/(m^2-n^2)等于多少?(要化简全过程)
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已知m/n = 5/3 求m/(m+n)+m/(m-n)-n^2/(m^2-n^2)等于多少?(要化简全过程)
"m/(m+n)+m/(m-n)-n^2/(m^2-n^2)=(m/n)/(1+m/n)+(m/n)/(-1+m/n)-1/((m/n)^2-1)=(5/3)/(1+5/3)+(5/3)/(5/3-1)-1/(25/9-1)=5/8+5/2-9/16=41/16追问请问 m/(m+n)+m/(m-n)-n^2/(m^2-n^2)
=(m/n)/(1+m/n)+(m/n)/(-1+m/n)-1/((m/n)^2-1) 怎么得到的"
=(m/n)/(1+m/n)+(m/n)/(-1+m/n)-1/((m/n)^2-1) 怎么得到的"
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