解不等式log2(4^x+1)>log(2^x+7)
解不等式log2(4^x+1)>log(2^x+7)
解不等式log2(2^x-1)log(2^x-2)
解不等式:√(log2(x-1))+log(1/2)(x^3)+2>0
已知x满足不等式log (1/2) x^2≥log(1/2) (3x-2).求函数f(x)=[log2 x/4]×(lo
解不等式2log2 (x-4)< log2 (x-2)
解不等式:(1/5)^[ (log2 X)^2-1] < (1/5)^[ 2x(2+log底数为根号2 X)
已知x满足不等式2[log2(x)]^2-7[log2(x)]+3≤0,求函数f(x)=[log2(x/2)]*[log
解不等式:log2(2x-1)
不等式log2(x^2-1)
解不等式 :(4/5)^(log2 X)^2-1
不等式|log2^x-1|
不等式log2 (x+1)