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已知-3≤㏒0.5(x)≤-(2/3),求函数f(x)=㏒2(x/2)*㏒2(x/4)的最大值和最小值

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已知-3≤㏒0.5(x)≤-(2/3),求函数f(x)=㏒2(x/2)*㏒2(x/4)的最大值和最小值
-3≤㏒0.5(x)≤-2/3
(1/2)^(-3/2)≤ x ≤ (1/2)^(-3)
2^(3/2) ≤ x ≤ 8
f(x)=㏒2(x/2)*㏒2(x/4)
max f(x)= f(8)
= ㏒2(4)*㏒2(2)
= 2
minf(x) = f(2^3/2)
=㏒2(2^(3/2)/2)*㏒2(2^(3/2)/4)
= (1/2).(-1/2)
= -1/4