数学(log5 √2log7 9)/(log5 1/3 log7 3√4)+log2( √(3+√5)- log√(

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数学(log5 √2*log7 9)/(log5 1/3 *log7 3√4)+log2( √(3+√5)- log√(3-√5))

数学(log5 √2*log7 9)/(log5 1/3 *log7 3√4)+log2( √(3+√5)- log√(3-√5))
=(lg√2/lg5 *lg9/lg7)/(lg1/3/lg5 *lg3√4/lg7)+log2( √( 3+√5)/√(3-√5))
=(1/2lg2/lg5 *2lg3/lg7)/(-lg3/lg5 *2/3lg2/lg7)+log2( ( 3+√5)/√(9-5))
=(lg2*lg3)/(lg5*lg7) /(-2/3*lg2*lg3/(lg5*lg7))+log2( ( 3+√5)/2)
=(lg2*lg3)/(lg5*lg7) *(-3/2*lg5*lg7/(lg2*lg3))+log2( ( 3+√5)/2)
=-3/2+lg ( 3+√5) -1
=-5/2+lg ( 3+√5)
再问：答案是-3/2
再答：题目这一段有误 log2( √(3+√5)- log√(3-√5))
再问：（1/2log5 2 乘 log2 9）/ （log5 1/3乘log7 4的立方根）我只是想知道这一块怎么解
再答： (log5 √2*log7 9)/(log5 1/3 *log7 3√4) 用换底公式 =(lg√2/lg5 *lg9/lg7)/(lg1/3/lg5 *lg3√4/lg7) =(1/2lg2/lg5 *2lg3/lg7)/(-lg3/lg5 *2/3lg2/lg7) =(lg2*lg3)/(lg5*lg7) /(-2/3*lg2*lg3/(lg5*lg7)) =(lg2*lg3)/(lg5*lg7) *(-3/2*lg5*lg7/(lg2*lg3)) =-3/2
再问： =(lg2*lg3)/(lg5*lg7) /(-2/3*lg2*lg3/(lg5*lg7)) 这步怎么来的
再答： =(lg√2/lg5 *lg9/lg7)/(lg1/3/lg5 *lg3√4/lg7) =(1/2lg2/lg5 *2lg3/lg7)/(-lg3/lg5 *2/3lg2/lg7) =(1/2*2*lg2*lg3/lg5*lg7)/(--2/3* lg3*lg2/lg5*lg7) =(lg2*lg3)/(lg5*lg7) /(-2/3*lg2*lg3/(lg5*lg7))

数学(log5 √2*log7 9)/(log5 1/3 *log7 3√4)+log2( √(3+√5)- log√( 我是这样做的log2(3)*log3(5)*log5(49)*log7(64)=log2(3)*log3(5)*2log log2(3)*log3(4)*log4(5)*log5(6)*log6(7)*log7(8)=? log2(3)+log3(4)+log4(5)+log5(6)+log6(7)+log7(8) （log5根号2底乘以log根号7底3 ）/log根号5底3分之1乘以log7底4的立方根求值 3^2-log3(2)= log7(log5(log2(32)))=? (log5根号2*log49 81)/(log25 1/3*log7 4开3次方）=? (log5根号2*log49^81)/(log25^(1/3)*log7^立方根4) 数学指数函数问题麻烦解释下y=log5(x+1) y=1/(log2(底数)X) y=log7(底数)1/(1-3x) log2为底3*log3为底4*log4为底5log5底6*log6底7*log7底8= log3 (4√27)/3 +lg25 +lg4 +7^(log7 2) (log3^4+log5^2)(log2^9+log2^根号3)