1)tan(3π-α)/sin(π-α)sin(3/2π-α)+sin(2π-α)cos(α-7/2π)/sin(3/2
1)tan(3π-α)/sin(π-α)sin(3/2π-α)+sin(2π-α)cos(α-7/2π)/sin(3/2
已知tanα=2,sinα+cosα<0,求[sin(2π-α)*sin(π+α)*cos(-π+α)]/[sin(3π
已知tan(3π+α)=2,求:1、(sinα+cosα)²;2、sinα-cosα/2sinα+cosα
1.已知cos(π/6-α)=1/3,求sin(2/3π-α) 2.求证tan^2α-sin^2α=tan^2α-sin
1、已知tan(3π+α)=2,求:(1)(sinα+cosα)²;(2)sinα-cosα/2sinα+co
已知tan(π-α)=2,求sinα-2sinαcosα-cosα/4cosα-3sinα的值
tanα=2,求sin(π-α)cos(2π-α)sin(-α+ 3π/2)/tan(-α-π)sin(-π-α)的值
已知tan(α+π/4)=2,则(2sinα+cosα)/(3cosα-2sinα)
已知tan(α+π/4)=2,求2cosα-sinα/cosα+3sinα
已知tan(α+π/4)=3,求cosα+2sinα/cosα-sinα的值
已知tanα=1/3,tan(π-β)=-1/2,sin(α+β)-2sinαcosβ除以2sinαsinβ+cos(α
..sin^2(π+α)*cos(π+α)*cos(-α-2π)/tan(π+α)*sin^3(π/2+α)*sin(-