作业帮∫(1,2)dx∫(√x,x)sin(πx/2y)dy+∫(2,4)dx+∫(√x,2)sin(πx/2y)dy
∫(1,2)dx∫(√x,x)sin(πx/2y)dy+∫(2,4)dx+∫(√x,2)sin(πx/2y)dy
y=sin[sin(x^2)] 则dy/dx=?
x=sin(y/x)+e^2 求dy/dx
∫（ e^x sin y- y )dx + (e^x cos y - 1)dy,是（2,0）的半圆周y=√2x-x^2
求∫dy/(2sin(y/2))=-∫sin(x/2)dx
计算二次积分:∫(1,3)dx∫(2,x-1)sin(y^2)dy
y=[sin(x^4)]^2,则dy/dx=?,dy^2/dx^2=?,dy/d(x^2)=?
y＝∫（x 1）sin（t∧2）dt,求dy/dx
y＝∫（1 -x）sin（t∧2）dt,求dy/dx
y=sin(x^2),dy/dx=?
∫(x^2-y)dx+(x+siny)dy
计算二次积分∫dy∫sin√(x^3)dx x[0,三次√π] y[y^2,三次√π^2]