3x+y+2z=10 2x+3y=-9 x+y+z=-6
试证明(x+y-2z)+(y+z-2x)+(z+x-2y)=3(x+y-2z)(y+z-2x)(z+x-2y)
如果|x+y+z-6|+|2x+3y-z-12|+|2x-y-z|=0求x,y,
x/2=y/3=z/5 x+3y-z/x-3y+z
x+y+z=4 2x+3y-z=6 3x+2y+2z=10
{x+y+z=6,2x-y+z=3,3x+9y+z=24
{2x+3y-4z=-5 x+y+z=6 x-y+3z=10
(x-2y+z)/9=(2x+y+3z)/10=-(3x+2y-4z)/3=1 连等,求x,y,z,
解方程组2x+y-3z=1,x-2y+z=6,3x-y+2z=9求x,y,z的值
已知x^3+y^3-6x+2y+z+3+10=0,求(x-y+z)(x+y-z)的值.(z+3)是绝对值
(4x-2y-z)-{5x[8y-2y-(x+y)]-x+(3y-10z)]=? kuai
3x+y+2z=10 2x+3y=-9 x+y+z=-6
已知x,y,z 大于0,x+y+z=2,求证 xz/y(y+z)+zy/x(x+y)+yx/z(z+x)大于等于2/3