计算:(1+1/x)·x²-2x+1/x²-1;(x²/x-1-2x/1-x)÷x/x-1
计算:(1+1/x)·x²-2x+1/x²-1;(x²/x-1-2x/1-x)÷x/x-1
2道分式计算[(x+4)(x-2)]/x³+2x²+x÷[(x-2)/x·(x+4)/(x+1)]2
计算:2x/(x-2)(x+1)÷(1-x/x+1)-x²+2x/x²-4?
[(x+2)/(x²+2x)-(x-1)/(x²-4x+4)]÷(x-4)/x
x(x²-1)+2x²(x+1)-3x(2x-5)计算
x+2/x²-2x-x-1/x²-4x+4计算
计算 ∫(x^4-2x^3+x^2+1)/x(x-1)² dx
计算:(1)x²/x-2 - 4x/x-2 + 4/x-2;
计算x²/x-1-x-1
计算【x-1】【x²+x+1】
(x+1-1/1-x)÷(x-x²/x-1) (x-4/x-x-6+ x+2/x-3)÷x+1/x-3
化简{x²-2x分之x+2-x²-4x+4x分之x-1}除以X分之(x-1)(X-4)乘以(2-x)