[xy+y²/5x²-5xy+xy+y²]*5x/x+y-y/x-y 分式过程

来源：学生作业帮编辑：拍题作业网作业帮分类：数学作业时间：2024/06/16 04:41:51

[(xy+y²)/(5x²-5xy)+xy+y²]*5x/(x+y)-y/(x-y)
=y(x+y)/5x(x-y)×5x/(x+y)+y(x+y)×5x/(x+y)-y/(x-y)
=y/(x-y)+5xy-y/(x-y)
=5xy

计算：(xy-x²)×x-y/xy x²/xy-x/y 分式（x²-y²\xy）-（xy-y²\xy-x²）可化简为 [-xy/(x-y)²]²×(y²-xy/x)³ x/xy-y²与y/x²-xy 通分分式计算:（x²+2xy+y²）/（x²y+xy）*y/（x+y）分式除法(2y-x)÷x²-4xy+4y²/x+3xy要过程化简（3X²-XY+Y²）-5(X²-XY+2Y²）若x-y=1,xy=5,则x²y-xy²=? 已知x-y=根号5,xy=二分之一,求x²-xy+y² -3(xy-2x²)-[y²-(5xy-4x²)+2xy] 因式分解x的5次方y-x³y+2x²y-xy

[xy+y²/5x²-5xy+xy+y²]*5x/x+y-y/x-y 分式 过程