如果1/2+1/6+1/12+.+1/n(n+1)=2003/2004 ,n=
(n+1)^n-(n-1)^n=?
Sn=n(n+2)(n+4)的分项等于1/6[n(n+2)(n+4)(n+5)-(n-1)n(n+2)(n+4)]吗?
如果f(n)=1/(n+1)+1/(n+2)+```1/2n (n属于N*) 那么f(n+1)-f(n)=
阶乘(2n-1)!=(2n)!/(2^n*n!
1 + (n + 1) + n*(n + 1) + n*n + (n + 1) + 1 = 2n^2 + 3n + 3
2^n/n*(n+1)
1\n(n+3)+1\(n+3)(n+6)+1\(n+6)(n+9)=1\2 n+18 n为正整数,求n的值
Dim n% n = 1 Do Until n > 6 Print n; n = n + 2.4 Loop
证明(1+2/n)^n>5-2/n(n属于N+,n>=3)
证明不等式:(1/n)^n+(2/n)^n+(3/n)^n+.+(n/n)^n
[3n(n+1)+n(n+1)(2n+1)]/6+n(n+2)化简
证明n^n-n(n-a)^(n-1)>=n!a.其中n>=a>0