作业帮(1)[(2y+1)(2y-1)]^2 (2)(x+y)(x^2+y^2)(x-y)(x^4+y^4) (3)(2x+y
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(1)[(2y+1)(2y-1)]^2 (2)(x+y)(x^2+y^2)(x-y)(x^4+y^4) (3)(2x+y+z)(y-2x-z)
解
[(2y+1)(2y-1)]²
=(4y²-1)²
=16y^4-8y²+1
(x+y)(x²+y²)(x-y)
=(x²-y²)(x²+y²)
=x^4-y^4
(2x+y+z)(y-2x-z)
=[y+(2x+z)][y-(2x+z)]
=y²-(2x+z)²
=y²-4x²-4xz-z² 再答： 第二题我看少了，重新输入给你
再答： (x+y)(x²+y²)(x-y)（x∧4+y∧4） =(x²-y²)(x²+y²)（x∧4+y∧4） =（x^4-y^4）（x∧4+y∧4）=x∧8-y∧8
[(2y+1)(2y-1)]²
=(4y²-1)²
=16y^4-8y²+1
(x+y)(x²+y²)(x-y)
=(x²-y²)(x²+y²)
=x^4-y^4
(2x+y+z)(y-2x-z)
=[y+(2x+z)][y-(2x+z)]
=y²-(2x+z)²
=y²-4x²-4xz-z² 再答： 第二题我看少了，重新输入给你
再答： (x+y)(x²+y²)(x-y)（x∧4+y∧4） =(x²-y²)(x²+y²)（x∧4+y∧4） =（x^4-y^4）（x∧4+y∧4）=x∧8-y∧8
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