题目是这样:sin(π/4x+π/4)+2sin[π/4(x+2)+π/4]
已知函数fx=(1+1/tanx)sin^x-2sin(x+π/4)sin(x-π/4)
化简2sin^2[(π/4)+x]+根号3(sin^x-cos^x)-1
y=sin(π/4+x/2)sin(π/4-x/2) =sin(π/4+x/2)sin[π/2-(π/4+x/2)]
已知函数f(x)=cos(2x-π/3)+2sin(x-π/4)sin(x+π/4)=sin(2x-π/6) ,
1、f(x)=sin^2(x+π/4)-sin^2(x-π/4)的最小正周期是?
函数f(x)=sin^2 (x+π/4)-sin^2 (x-π/4) 周期是多少 是奇函数还是偶函数
已知函数f(x)=(1+cotx)sin^2(x)-2sin(x+π/4)sin(x-π/4)
已知函数f(x)=sin^2 x+2根号3sinxcosx+sin(x+π/4)sin(x-π/4),x属于R,求f(x
已知f(x)=cos^2x+sinxcosx g(x)=2sin(x+π/4)sin(x-π/4)
数学题目已知函数f(x)=+2sinωxcosωx+2f(a)=2/3求sin(5/6π-4a)
已知函数f(1+cotx)sinx^2-2sin(x+π/4)sin(x-π/4)
1.已知sin(π/6-x)=1/4,sin(π/6+2x)=?