三角函数求极限limit(n趋向于无限大) n*sin(2兀/n)要求背景知识,解法和思路,
求当n趋向无限大时lim[(n+1)^2/(n-1)]的极限?
求极限 lim( √N^2+N )-N X趋向于无穷 求极限
求极限 n趋向于无穷 lim((根号下n^2+1)/(n+1))^n
求极限lim(n趋向于无穷)(n+1)(根号下(n^2+1)-n)
求极限 lim n[1/(n^2+1)+1/(n^2+2^2)+……+1/(n^n+n^n)] (n趋向于无穷大,n^n
求极限 n*sin(x/n) n趋向无穷
n趋向于无穷大时,极限LIM(n^2)sin^2(Θ/n)=-(Θ^2)/2 求具体过程.
求(3n-sin(n^2))/(2n+cos(n^2))的极限,当n趋于无限大时
lim[(根号下n^2+n)-n],n趋向于无穷,求函数的极限
求极限(n+4/n+3)∧2n.n趋向于无穷大
求极限根号下n的平方加上2n减去n.n趋向于无穷大.
求极限:Lim(1+1/n-1/n^2)^n n趋向于正无穷