1.y(x+y)+(x-y)^2-x^2-2y^2

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1.y(x+y)+(x-y)^2-x^2-2y^2
2.(x^3+4)^2-16(x-1)(x+1)-(x^3-4)^2
3.x^3-x
4.-2(m-n)^2+32
5.(a+2b)^2-4(a-b)^2

答：
1.原式
=xy+y^2+x^2+y^2-2xy-x^2-2y^2
=-xy
2.原式
=x^6+8x^3+16-16x^2+16-x^6+8x^3-16
=16x^3-16x^2+16
=16(x^3-x^2+1)
3.原式
=x(x^2-1)
=x(x+1)(x-1)
4.原式
=2[16-(m-n)^2]
=2(4+m-n)(4-m+n)
5.原式
=(a+2b-2a+2b)(a+2b+2a-2b)
=3a(4b-a)

1、x(x-y)(x+y)-x(x+y)^2 1.[(x-y)^2-2(y -x)]÷(x-y) 1.(x-2y)(x+2y)-(x平方+y)(x平方-y) 2.(2x-y)(y+2x)-(2y+x)(2y-x) [(-x-y)(-x+y)-(x+y)^2-x(y-y^2)}÷1/2y (1)(x^2/x)-y-x-y 【(x-y)^2+(x+y)(x-y)】除以 2x x^2-y^2/x+y-4x(x-y)+y^2/2x-y, (x+y)^2(x-y)^2-(x-y)(x+y)(x^2+y^2)分解因式化简:(x-3y)(x+y)-(x-2y)(x+2y)-(x-y)平方【x-3y][x+y]-[x-2y][x +2y]-[x-y [(3x+y)(x-y)-(2x+3y)(x-y)]*(x-y) 有这样一道题:"计算(2*x*x*x-3*x*x*y-2*x*y*y)-(x*x*x-2*x*y*y+y*y*y)+【-