计算: (1)(x-1)(x+1)=x²-1, (x-1)(x²+x+1)=x³-1
计算下列各题:(1+x)(x-1/x²+x-1-x/x³-x)
计算x²/x-1-x-1
计算【x-1】【x²+x+1】
计算(x²+x+1)(x²-x+1)
计算:(3/x)+(x/x²-1)-(4/1-x)
x²(x²-x+1)-x(x³-x²+x+1)其中x=-1
计算2x/(x³-1)÷1/(x²+x+1)=
x³-x²/x²+x÷(x²-1) 计算
2道分式计算[(x+4)(x-2)]/x³+2x²+x÷[(x-2)/x·(x+4)/(x+1)]2
计算:(1+1/x)·x²-2x+1/x²-1;(x²/x-1-2x/1-x)÷x/x-1
若1+x+x*x+x*x*x=0,求x+x*x+x*x*x+.+x(2000次幂)
x(x²-1)+2x²(x+1)-3x(2x-5)计算