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Let G be a connected undirected graph with at least 3 vertic

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Let G be a connected undirected graph with at least 3 vertices,and let G^3 be the graph obtained by connecting all pairs of vertices that are connected by a path in G of length at most 3.prove that G^3 is hamiltonian.(hint:construct a spanning tree for G,and use an inductive arguement)
设G是一个连通无向图,至少3个顶点,并令G ^ 3,通过连接是通过一个连接的长度G路径最多3个顶点都对得到的图.证明了G ^ 3是哈密尔顿.(提示:建立一个G的生成树,并使用一个电感参数)
说实话,我不懂你这个题是什么意思没有学过