[sin(5π-α)cos(-π-α)]/[cos(α-π)cos(π/2+α)]化简
(1+sinα+cosα)*[sin(α/2)-cos(α/2)]/√(2+2cosα)化简 (3/2*π
化简sin(α-5π)/cos(3π-α)×cos(π/2-α)/sin(α-3π)×cos(8π-α)/sin(-α-
化简{sin(π+α)^3cos(-α)cos(π+α)}/{tan(π+α)^3cos(-π-α)^2}
化简:[ cos(α-π/2)/sin(5π/2+α) ] ×sin(α-2π) × cos(2π-α)
①化简[sin(2π+α)*cos(7π-α)]/cos(-α)②已知cosθ=-3/5,θ∈(π/2,π),求sin(
1.化简sin²α+cosαcos(π/3+α)-sin²(π/6-α)
化简:sinα-√3 cosα+2cos(α-π/3)
化简:cos(-π-α)
化简[sin(π/2-α)cos(π/2-α)]/cos(π+α)-[sin(π-α)cos(π/2-α)]/sin(π
比较大小sin(cosα)与cos(sinα)(0<α<π/2)
α∈(0,π/2 ),比较 sin(cosα) 与cos(sinα)大小
已知cos(π/2+α)=sin(α-π/2) 求sin(π-α)-cos(π+α)/cos(5π/2 -α)+2sin