微积分问题四题y = −x^7 +1/ x^3 −(5次方√x)y = 5cos(4x^3
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微积分问题四题
y = −x^7 +1/ x^3 −(5次方√x)
y = 5cos(4x^3− 1)tan(x)
y = sin√(x^2 − 7x^−1)
y =3e^x− 2x^3/3e^x + 2x^3
y = −x^7 +1/ x^3 −(5次方√x)
y = 5cos(4x^3− 1)tan(x)
y = sin√(x^2 − 7x^−1)
y =3e^x− 2x^3/3e^x + 2x^3
y=-x^7+1/x^3-x^(1/5), y'=-7x^6-3/x^4-(1/5)x^(-4/5).y=5cos(4x^3-1)tanx, y'=-60x^2sin(4x^3-1)tanx+5cos(4x^3-1)(secx)^2.y=sin√[x^2 − 7x^(−1)], y'={[x+7/(2x^2)]/√[x^2 − 7x^(−1)]}cos√[x^2 − 7x^(−1)].y =3e^x− 2x^3/(3e^x) + 2x^3, y'=3e^x-(2/3)(3x^2-x^3)/e^x+6x^2
再问: 可否把过程写出,我再加你30分,最好写在纸上拍张照片传上来。
再答: y=-x^7+1/x^3-x^(1/5)=-x^7+x^(-3)-x^(1/5) y'=-7x^(7-1)-3x^(-3-1)-(1/5)x^(1/5-1) =-7x^6-3/x^4-(1/5)x^(-4/5).y=5cos(4x^3-1)tanx, y'=-5sin(4x^3-1)(4x^3-1)' tanx+5cos(4x^3-1)(tanx)'= -60x^2sin(4x^3-1)tanx+5cos(4x^3-1)(secx)^2.y=sin√[x^2 − 7x^(−1)], y'=cos√[x^2 − 7x^(−1)] {√[x^2 − 7x^(−1)] }' = {[x+7/(2x^2)]/√[x^2 − 7x^(−1)]}cos√[x^2 − 7x^(−1)].y =3e^x− 2x^3/(3e^x) + 2x^3 = 3e^x− (2/3)x^3e^(-x) + 2x^3y'=3e^x-(2/3)[3x^2e^(-x)-x^3e^(-x)]+6x^2 =3e^x-(2/3)(3x^2-x^3)/e^x+6x^2.这都是很简单的复合函数求导内容,建议你先看一看高等数学教科书复合函数求导一小节再做题吧。
再问: 可否把过程写出,我再加你30分,最好写在纸上拍张照片传上来。
再答: y=-x^7+1/x^3-x^(1/5)=-x^7+x^(-3)-x^(1/5) y'=-7x^(7-1)-3x^(-3-1)-(1/5)x^(1/5-1) =-7x^6-3/x^4-(1/5)x^(-4/5).y=5cos(4x^3-1)tanx, y'=-5sin(4x^3-1)(4x^3-1)' tanx+5cos(4x^3-1)(tanx)'= -60x^2sin(4x^3-1)tanx+5cos(4x^3-1)(secx)^2.y=sin√[x^2 − 7x^(−1)], y'=cos√[x^2 − 7x^(−1)] {√[x^2 − 7x^(−1)] }' = {[x+7/(2x^2)]/√[x^2 − 7x^(−1)]}cos√[x^2 − 7x^(−1)].y =3e^x− 2x^3/(3e^x) + 2x^3 = 3e^x− (2/3)x^3e^(-x) + 2x^3y'=3e^x-(2/3)[3x^2e^(-x)-x^3e^(-x)]+6x^2 =3e^x-(2/3)(3x^2-x^3)/e^x+6x^2.这都是很简单的复合函数求导内容,建议你先看一看高等数学教科书复合函数求导一小节再做题吧。
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