n=n>=(count-1)?0:
[N-1:0]count是什么意思?
证明n^n-n(n-a)^(n-1)>=n!a.其中n>=a>0
(n+1)^n-(n-1)^n=?
int[] a = {1,2,3,4,5}; for (int count = 0; count < 5; count+
for (count=MAX_NUMBER+1; count!=0; count--) 这句什么意思
count+=count++是什么意思?
求教,N^0+N^1+N^2+N^3.N^n=?公式是什么?(N≠n且N,n都属于自然数)
求证:C(0,n)+2C(1,n)+.+(n+1)C(n,n)=2^n+2^(n-1)
组合:C(n,0)+C(n,1)+……+C(n,n)=n^2
公式:=IF(ISERROR(SUM(D3:D7)/(COUNT(D3:D7)*10)),"N/A",SUM(D3:D7
n*n-65n+636=0
证明:(n+1)n!= (n+1)!