作业帮3/8*log3/8+1/4*log1/4 怎么算
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3/8*log3/8+1/4*log1/4 怎么算
(3/8)log(3/8)+(1/4)log(1/4)
=(3/8)[log3-3log2]+(1/4)[-2log2]
=(3/8)log3 -(13/8)log2
再问： 可以继续算下去吗？ 那3/8*log3/8+1/4*log1/4+1/4*log1/4+1/8*log1/8=?
再答： 3/8*log3/8+1/4*log1/4+1/4*log1/4+1/8*log1/8 =(3/8)(log3-3log2)+(1/2)(-2log2) +(1/8)(-3log2) =(3/8)log3 - (20/8)log2
=(3/8)[log3-3log2]+(1/4)[-2log2]
=(3/8)log3 -(13/8)log2
再问： 可以继续算下去吗？ 那3/8*log3/8+1/4*log1/4+1/4*log1/4+1/8*log1/8=?
再答： 3/8*log3/8+1/4*log1/4+1/4*log1/4+1/8*log1/8 =(3/8)(log3-3log2)+(1/2)(-2log2) +(1/8)(-3log2) =(3/8)log3 - (20/8)log2
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