如果,n是大于2的整数,计算1/(n-1)(n-2)+1/(n-2)(n-3)+1/(n-3)(n-4)+……+1/(n
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如果,n是大于2的整数,计算1/(n-1)(n-2)+1/(n-2)(n-3)+1/(n-3)(n-4)+……+1/(n-2010)(n-2011)
1/(n-1)(n-2)+1/(n-2)(n-3)+1/(n-3)(n-4)+……+1/(n-2010)(n-2011)
=-1/(n-1)+1/(n-2)-1/(n-2)+1/(n-3)-1/(n-3)+1/(n-4)-...-1/(n-2010)+1/(n-2011).裂项
=-1/(n-1)+1/(n-2011).消去中间项
=-(n-2011-n+1)/(n-1)(n-2011)
=2010/(n-1)(n-2011)
=-1/(n-1)+1/(n-2)-1/(n-2)+1/(n-3)-1/(n-3)+1/(n-4)-...-1/(n-2010)+1/(n-2011).裂项
=-1/(n-1)+1/(n-2011).消去中间项
=-(n-2011-n+1)/(n-1)(n-2011)
=2010/(n-1)(n-2011)
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