英语翻译so far we have the "vinculum numbers " :1,2,5,14b) begin

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英语翻译
so far we have the "vinculum numbers " :1,2,5,14
b) begin listing all the ways to place vinculums over a sum of six numbers.Do this in a systematic manner and see if you can explain why the count of possibilities is :
1 x 14 +1 x 5 + 2 x 2 + 5 x 1 + 14 x 1 = 42
c）What is the next vinculum number after this And the next
d）Is there an explicit formula for the n th vinculum number

到目前为止,我们有的一组相关数是：1,2,5,14
b）列出所有相关数超过六个数字的总和的方式.系统的列出这些方式,并解释这种计数方式的可能性：
1×14+1×5+2×2+5×1+14×1=42
c）相关数的下一个数应该是什么?再下一个呢?
d）求第n个相关数的公式?
再问：并解释这种计数方式的可能性是什么意思？求第n个相关数的公式又是什么意思啊？你能看懂这个题目吗？我要解释T^T
再答：我给你算，记得给我好评，先谢谢了相关数的规律推导_: 1前边没数，先不考虑 2=1*2+(1-1) 5=2*2+(2-1) 14=5*2+(5-1) 到这就可以看到这组相关数的规律了所以14下一个数是 14*2+（14-1）= 41, 再下一个数是 41*2+ （41-1）= 122 所以第n个数等于第n-1个数的2倍加上第n-1个数减去1 你b小题里那个算式是题中给出的么？问题里说的是超过六个相关数的和，现在这个式子里只有4个相关数

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