作业帮初二数学题：分式计算
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初二数学题：分式计算
12/(m²-9)-2/(3-m)
=12/(m-3)(m+3)+2(m+3)/(m+3)(m-3)
=(12+2m+6)/(m-3)(M+3)
=2(m+9)/(m-3)(m+3)
[(x²-4)/(x²-4x+4)-(x-2)/(x+2)]÷x/(x-2)
=[(x²-4)(x+2)/(x-2)²(x+2)-(x-2)³/(x-2)²(x+2)]÷x/(x-2)
=[(x³-4x+2x²-8-x³+6x²-12x+8)/(x-2)²(x+2)]÷x/(x-2)
=(8x²-16x)/(x-2)²(x+2)÷x/(x-2)
=2x(x-2)/(x-2)²(x+2)÷x/(x-2)
=2/(x+2)
1/(y-x)+1/(2x-2y)
=2/2(y-x)-1/2(y-x)
=(2-1)/2(y-x)
=1/2(y-x)
=12/(m-3)(m+3)+2(m+3)/(m+3)(m-3)
=(12+2m+6)/(m-3)(M+3)
=2(m+9)/(m-3)(m+3)
[(x²-4)/(x²-4x+4)-(x-2)/(x+2)]÷x/(x-2)
=[(x²-4)(x+2)/(x-2)²(x+2)-(x-2)³/(x-2)²(x+2)]÷x/(x-2)
=[(x³-4x+2x²-8-x³+6x²-12x+8)/(x-2)²(x+2)]÷x/(x-2)
=(8x²-16x)/(x-2)²(x+2)÷x/(x-2)
=2x(x-2)/(x-2)²(x+2)÷x/(x-2)
=2/(x+2)
1/(y-x)+1/(2x-2y)
=2/2(y-x)-1/2(y-x)
=(2-1)/2(y-x)
=1/2(y-x)