求 lim ln(1+x+2x^2)+ln(1-x+x^2)/secx-cosx
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求 lim ln(1+x+2x^2)+ln(1-x+x^2)/secx-cosx
=lim cosx·ln[(1+x+2x^2)·(1-x+x^2)]/(1-cos²x)
=1×lim ln[1+(x+2x^2)+(-x+x^2) +(x+2x^2)·(-x+x^2)]/(sin²x)
=lim ln[1+3x^2 +x²·(1+2x)·(-1+x)]/x²
=lim [3x^2 +x²·(1+2x)·(-1+x)]/x²
=lim [3+(1+2x)·(-1+x)]
= 3+(1+2×0)·(-1+0)
=2
=1×lim ln[1+(x+2x^2)+(-x+x^2) +(x+2x^2)·(-x+x^2)]/(sin²x)
=lim ln[1+3x^2 +x²·(1+2x)·(-1+x)]/x²
=lim [3x^2 +x²·(1+2x)·(-1+x)]/x²
=lim [3+(1+2x)·(-1+x)]
= 3+(1+2×0)·(-1+0)
=2
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