f(x)=[(1+x)/(1-x)]e^(-ax)求导

来源：学生作业帮编辑：拍题作业网作业帮分类：数学作业时间：2024/04/28 07:47:13

f'(x) = [(1+x)/(1-x)]'e^(-ax) + (-ae^-ax)[(1+x)/(1-x)]
= [(1+x)/(1-x)]'e^(-ax) - ae^(-ax) * (1+x)/(1-x)
= [-(x-1+2)/(x-1)]'e^(-ax) - ae^(-ax) * (1+x)/(1-x)
= [-(x-1)/(x-1)-2/(x-1)]'e^(-ax) - ae^(-ax) * (1+x)/(1-x)
= (2/(x-1)^2)e^(-ax) - ae^(-ax) * (1+x)/(1-x)

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