( )1、A、t_ea_cher B、eight_ee_n C、h_ea_d D.pl_ea_se
( )1、A、t_ea_cher B、eight_ee_n C、h_ea_d D.pl_ea_se
[a,b)×[c,d
a,b ,c ,d
A B C D × 9 ___________________ D C B A (1) A = ( )(2) B = (
一直a>b>c>d,则(1/(a-b)+1/(b-c)+1/(c-d))*(a-d)的最小值
( )-(c-d)=(a-c)-(-b+d)
定义区间(c,d),[c,d),(c,d],[c,d]的长度均为d-c(d>c).已知实数a>b,则满足1/(x-a)+
已知a>b>c>d,求证1/a-b+1/b-c+1/c-a>=9/a-d
a=b=c=1; a+=b*=c%=a+b+c; printf("%d,%d,%d\n",a,b,c) 计算顺序
设a,b,c满足ab+bc+cd+da=1,求证:a^3/(b+c+d)+b^3/(a+c+d)+c^3/(a+b+d)
#include main() { int a,b,c; scanf("%d,%d",&a,&b); if(a>b+1)
分解因式(a-b)(c+d)-(a-b)(c-d)