(1/37+1/41+1/43+1/47+1/53)*(1/41+1/43+1/47+1/53+1/54)-(1/37+
来源:学生作业帮 编辑:拍题作业网作业帮 分类:数学作业 时间:2024/04/28 02:53:51
(1/37+1/41+1/43+1/47+1/53)*(1/41+1/43+1/47+1/53+1/54)-(1/37+1/41+1/43+1/47+1/53+1/54)*(1/41+
接上:1/43+1/47+1/53)
接上:1/43+1/47+1/53)
=(1/37+1/41+1/43+1/47+1/53)*(1/41+1/43+1/47+1/53)+(1/37+1/41+1/43+1/47+1/53)*(1/54)-(1/37+1/41+1/43+1/47+1/53)*(1/41+1/43+1/47+1/53)-(1/54)*(1/41+1/43+1/47+1/53)
=(1/37+1/41+1/43+1/47+1/53)*(1/54)-(1/54)*(1/41+1/43+1/47+1/53)
=(1/54)*(1/37)
=1/1998
=(1/37+1/41+1/43+1/47+1/53)*(1/54)-(1/54)*(1/41+1/43+1/47+1/53)
=(1/54)*(1/37)
=1/1998
(1/37+1/41+1/43+1/47+1/53)*(1/41+1/43+1/47+1/53+1/54)-(1/37+
[(1/31+1/37+1/41+1/47+1/53+1/69)*(1/29+1/31+1/37+1/41+1/47+1
37×(1/80+1/43)-43×(1/37-1/80)+80×(1/37-1/43)简便计算
在(1/17+1/19)*20,(1/24+1/29)*30,(1/31+1/37)*40,(1/41+1/47)*50
1+3+5+7+9+11+13+15+17+19+21+25+27+29+31+35+37+39+41+43+47+49
(1)1+3+5+7+.+(2n-1)+(2n+1)=?(2)41+43+45+47+.+77+79=?
填空题 (1 9:53:41)
43又20分之1除以41
37×(80分之1+43分之1)-43×(37分之1-80分之一)+80×(37分之1-43分之1)要单便方法
简便方法计算:(1)1998+998+98=(2)43+40+39+41+37+42=
2又47分之12-1又53分之41除以(2分之1+3分之1)除以11又4分之3等于
37/43-(30/43+1/3) 简便计算