求【2sin50度+sin10度(1+根号3tan10度)】sin80度的值
来源:学生作业帮 编辑:拍题作业网作业帮 分类:数学作业 时间:2024/05/02 22:04:03
求【2sin50度+sin10度(1+根号3tan10度)】sin80度的值
【2sin50°+sin10°(1+根号3tan10°)】sin80°
=【2sin50°+sin10°(1+tan60°tan10°)】sin80°
=【2sin50°+sin10°(1+sin60°sin10°/cos60°cos10°)】sin80°
=【2sin50°+sin10°((cos60°cos10°+sin60°sin10°)/cos60°cos10°)】sin80°
=【2sin50°+sin10°((cos50°)/cos60°cos10°)】sin80°
=【2sin50°+2sin10°cos50°/cos10°】sin80°
=【(2sin50°cos10°+2sin10°cos50°)/cos10°】sin80°
=[2sin60°/cos10°]sin80°
=√3sin80°/cos10°
=√3sin80°/sin80°
=√3
=【2sin50°+sin10°(1+tan60°tan10°)】sin80°
=【2sin50°+sin10°(1+sin60°sin10°/cos60°cos10°)】sin80°
=【2sin50°+sin10°((cos60°cos10°+sin60°sin10°)/cos60°cos10°)】sin80°
=【2sin50°+sin10°((cos50°)/cos60°cos10°)】sin80°
=【2sin50°+2sin10°cos50°/cos10°】sin80°
=【(2sin50°cos10°+2sin10°cos50°)/cos10°】sin80°
=[2sin60°/cos10°]sin80°
=√3sin80°/cos10°
=√3sin80°/sin80°
=√3
求【2sin50度+sin10度(1+根号3tan10度)】sin80度的值
求[2sin50度+sin10度(1+根号3*tan10度)]*根号下2倍sin80度的平方 的值
[2sin50°+sin10°(1+√3tan10°)]*√2(sin80°)*(sin80度)
[2sin50+sin10(1+根号3tan10)]sin80
求[2sin50°+sin10°(1+√3tan10°0]sin80°的值
化简【2sin50°+sin10°(1+根号3tan10°)】乘根号下2(sin80°的平方)
求(1/sin10度)-(根号3/sin80度)的值
求值:[2sin50°+sin10°(1+√3tan10°)]×√2sin80°
求值[2sin50°+sin10°(1+√3tan10°)]*√2(sin80°)*(sin80°)
化简[2sin50°+sin10°(1+根号三tan10°)]*根号[2(sin80°)平方]拜托了各位
请问这个题怎么解?sin50°+sin10°(1+根号3*tan10°)根号下2*sin80°平方
化简sin50度[1+(根号3)tan10度] 第一步=sin50(cos10+√3sin10)/cos10 第二步是