{x﹣y=13,x=6y﹣7

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已知x,y满足:x平方+y平方-4x+6y+13=0求(3x+y)-3(3x-y)(x+y)-(x-3y)(x+3y)=

x平方+y平方-4x+6y+13=0(x-2)^2+(y+3)^2=0x=2,y=-3;带入要求的表达式即可.再问:怎么算出x=2y=-3的???再答:例如:a^2+b^2=0就只有a=0,b=0才成

2(x+y)-3(x-y)=1 6(x+y)+7(x-y)=51 解方程组

(用换元法)设A=x+y,B=x-y原方程组可化为2A-3B=1,6A+7B=51解得A=5,B=3即x+y=5,x-y=3解得x=4,y=1

已知x*x+y*y-4x-6y+13=0,求3x+4y的值

x*x+y*y-4x-6y+13=0可以化为:(x-2)^2+(y-3)^2=0只有在x=2、y=3时,上式才能成立.代入3x+4y=3*2+4*3=18

x-y=13 x=6y-7

将x=6y-7代入得6y-7-y=135y=20y=4x=24-7=17

解方程组6x+7y=﹣19,5y-6x=﹣17

6x+7y=﹣19(1)5y-6x=﹣17(2)(1)+(2)得12y=-36y=-3代入(1)得6x-21=-196x=2x=1/3

2X+Y+Z=10,X+2Y+Z=-6,X+Y+2Z=8 5X+4Y-3Y=13,2X-3Y+7Z=19,3X-Y=2X

2x+y+z=10(1)x+2y+z=-6(2)x+y+z=8(3)(2)-(3):y=-14(4)(1)-(2):x-y=16(5)把(4)代入(5):x+14=16x=2(6)把(4)和(6)代入

解二元一次方程组:{5(x+y)+3(x-y)=2{7(x+y)-3(x-y)=-6

{5(x+y)+3(x-y)=2{7(x+y)-3(x-y)=-6原方程组化简得﹛4x+y=1(1)2x+5y=-3(2)(1)×5得20x+5y=5(3)(3)-(2)得18x=8x=4/9代入(1

2(x+y)-3(x-y) =1 6(x+y)+7(x-y)=51大神们帮帮忙

一式乘3减二式得x-y=-3带x-y入两式你应该会做了

已知(x-y)/13=y/7,则(x+y)/y=

第一题:(x-y)/13=y/713y=7x-7y20y=7xx/y=20/7两边都加1(x+y)/y=27/7第二题:x/6=y/4=z/3(x,y,z,不为零)用特值法令x/6=y/4=z/3=1

X+Y=9 6X+7Y=59

(2)-(1)×6得y=5把y=5代入(1)得x=4∴方程组的解是x=4y=5再问:0.5(X-0.2)=0.9X-1.78再答:0.5x-0.1=0.9x-1.781.77=0.4x∴x=4.425

若x、y满足2x+y=6,x-3y=1,求7y(x-3y)²-2(3y-x)³的值

7y(x-3y)²-2(3y-x)³=7y(x-3y)²+2(x-3y)³=(x-3y)²[7y+2(x-3y)=(x-3y)²(7y+2X

若(x-y)/(x+y)=3 则(x+2y)/(6x-7y)等于

若(x-y)/(x+y)=3那么x-y=3(x+y)x-y=3x+3y故x=-2y所以(x+2y)/(6x-7y)=(-2y+2y)/(6*(-2y)-7y)=0如果不懂,请Hi我,祝学习愉快!

已知x²+4y²-6x+8y+13=0,求x-y/x+y的值.

x²+4y²-6x+8y+16=0(x²-6x+9)+4(y²+2y+1)=0(x-3)²+4(y+1)²=0x-3=0,y+1=0x=3,

解方程组﹛2(x+y)-3(x-y)=1 6(x+y)+7(x-y)=51

因为2(x+y)-3(x-y)=1所以2x+2y-3x+3y=1-x+5y=1x=5y-1因为6(x+y)+7(x-y)=51所以6x+6y+7x-7y=5113x-y=51将x=5y-1代入13x-

解方程组(x+y)(x-2y)=-5 (x-y)(x+2y)=7

展开x^2-2y^2-xy=-5x^2-2y^2+xy=7所以x^2-2y^2=1xy=6上式除以下式,解分式方程x/y=3/2或-4/3(舍去)所以x^2=9y^2=4x=3y=2或x=-3y=-2

x+y=3 x+2y=9 3/x+1=y y-x=3 y=2x-3 y-3x=1 2(x+1)-y=6 7x-5y=-9

x+y=3则y=3-x带入x+2y=9解得x=-3,y=6剩下的都这样解

已知x,y满足x²+y²-4x+6y+13=0则(3x+y)²-(3x+y)(3x-y)的

x²+y²-4x+6y+13=0x²-4x+4+y²+6y+9=0(x-2)²+(y+3)²=0x=2,y=-3代入即可得出答案(3x+y)