y=x的三分之二次方周期
来源:学生作业帮助网 编辑:作业帮 时间:2024/04/30 11:28:42
y·x^¾再问:可以有过程吗?再答:(x^¼xy^1/3)/[x^½y^(﹣2/3)]=x^¼x^(1-½)y^[1/3-(﹣2/3)
y=(sinx)^4+(cosx)^4=[(sinx)^2+(cosx)^2]^2-2(sinx)^2(cosx)^2=1-(1/2)[sin(2x)]^2=1-(1/4)2[sin(2x)]^2=1
y=f(x)=(sinx)^4+(cosx)^4=[(1-cos2x)/2]^2+[(1+cos2x)/2]^2=(1/2)[1+(cos2x)^2]=(1/2){1+(1+cos4x)/2}=(1/
令m=a三分之一次方n=b三分之一次方则m²+n²=4x=m³+3mn²y=n³+3m²n则x+y=m³+3m²n+3m
x+y=a+3a^(1/3)*b^(2/3)+b+3a^(2/3)*b^(1/3)=[a^(1/3)+b^(1/3)]^3x-y=a+3a^(1/3)*b^(2/3)-b-3a^(2/3)*b^(1/
x+y=a+3a^(1/3)*b^(2/3)+b+3a^(2/3)*b^(1/3)=[a^(1/3)+b^(1/3)]^3x-y=a+3a^(1/3)*b^(2/3)-b-3a^(2/3)*b^(1/
y=sin^6x+cos^6=(sin^2x+cos^2x)(sin^4x-sin^2xcos^2x+cos^4x)=sin^4x-sin^2xcos^2x+cos^4x=sin^4x+2sin^2x
y=sin⁴x-cos⁴x=(sin²x+cos²x)(sin²x-cos²x)=sin²x-cos²x=-cos2
(-二分之一x的平方y)的-2次方×(-三分之二xy的平方)的-1次方=(4分之1x的4次幂y²)的-1次幂×(-2分之3x的-1次幂y的-2次幂)=4x的-4次幂y的-2次幂×(-2分之3
(2/3)^2002x(3/2)^2003÷(-1)的2004=[(2/3)^2002x(3/2)^2002x(3/2)]÷1=3/2即是说:先把(3/2)^2003=(3/2)^2002x(3/2)
由|2x/3-6|+|0.2+2y|=0,可知:2x/3-6=,x=9,0.2+2y=0,y=-0.1,∴x²+y²=9²+(0.1)²=81.0.01
y^(2/3)=x[y^(2/3)]^(3/2)=y=x^(3/2)
lim[(x+dx)^(2/3)-x^(2/3)]/dx=lim[(x+dx)^2-x^2]/{[(x+dx)^(4/3)+x^(2/3)*(x+dx)^(2/3)+x^(4/3)]*dx}=lim(
y=(2/3)^-|x|是个偶函数只要算出x>=0的一部分值域即可x>=0y=(2/3)^-x=(3/2)^x>=0所以值域是y>=1
y=(x-1)^(-2/3)=1/(x-1)^(2/3)定义域为x>1及x1单调减在x
解题思路:三角函数的周期公式解题过程:
4次方是是这样表示的cos^4首先常数项是不影响周期的,cos^4(x)-sin^4(x)=[cos^2(x)+sin^2(x)][cos^2(x)-sin^2(x)]=cos^2(x)-sin^2(
偶化成y=根3下x的平方那样不管X是正还是负平方了都是正再开三次方所以偶
x+x^(-1)=3二边平方得:x^2+x^(-2)+2=9x^2+x^(-2)=7[x^2/3]^3+[x^(-2/3)]^3=7[x^2/3+x^(-2/3)][(x^2/3+x^(-2/3))^
-0.5X^(a+b)y^(a-b)与2/3x^(a-1)是同类项a+b=(a-1)a-b=0a=-1b=-1