作业帮y=sin(2x 3),则dy=
来源：学生作业帮助网 编辑：作业帮 时间：2024/04/28 00:09:54
sin(x^2+y^2)=x两边同时求导,得(x^2+y^2)'cos(x^2+y^2)=dx(2xdx+2ydy)cos(x^2+y^2)=dx2xdx+2ydy=dx/cos(x^2+y^2)2y
y'=2xsin4x-x²cos4x·4所以dy=(2xsin4x-4x²cos4x)dxy=ln√4＋t²=1/2ln(4+t²)y'=1/2·1/(4+t&
dy什么意思?再问：对y的求导再答：（2x+2^x）cos（2x+2^x）
设x^2=a则y=sin(a^2)∴dy/d(x^2)=dy/da=dsin(a^2)/da=cos(a^2)*da^2/da=2acos(a^2),将a=x^2代入式中即可得dy/d(x^2)=2x
x=sin(y/x)+e^2求dy/dxd(x)=d(sin(y/x)+e^2)dx=dsin(y/x)+de^2dx=cos(y/x)d(y/x)dx=cos(y/x)(xdy-ydx)/x^2x^
dy/dx相当于对x进行求导：dy/dx=y'=2x*cos[sin(x^2)]*cos(x^2)由于：sinx=cosx,sin(x^2)=2x*cos(x^2)
你只要知道arcsinx和sinx的原函数不就能求解了吗再问：还是不懂能写写过程么再答：你都求到这一步∫dy/(2sin(y/2))=-∫sin(x/2)dx了，答案不就在下一步么再问：等式左边积分不
加油啊,不然大学考不起啊!
y=x*sin(lnx)y'=sin(lnx)+x*cos(lnx)*(lnx)'=sin(lnx)+x*cos(lnx)*1/x=sin(lnx)+cos(lnx)dy=[sin(lnx)+cos(
dy=2sin[x(x+1)]cos[x(x+1)](2x+1)
y'=f'(sin^2x)*(sin^2x)'=g(sin^2x)*2sinxcosx
dy=cos(x^2-1)(x^2-1)'dx=cos(x^2-1)*2xdx=2xcos(x^2-1)dx
dy/dx=2sin(x^4)cos(x^4)*4x^3复合函数求导dy^2/dx^2=[8x^3sin(x^4)cos(x^4)]^2dy/d(x^2)=2sin(x^4)cos(x^4)*2x^2
y+xy'-cos(πy²)2πyy'=0y=[2πycos(πy²)-x]y'y'=y/[2πycos(πy²)-x]即：dy/dx=y/[2πycos(πy²
y=sin(x+y)dy=cos(x+y)(dx+dy)dy=cos(x+y)dx+cos(x+y)dydy/dx=cos(x+y)/(1-cos(x+y))
1dy/dx=(x+y)/(x-y)y=xudy=xdu+udxxdu+udx=(1+u)/(1-u)dxxdu=[(1+u)/(1-u)-u]dx(1-u)du/(1+u^2)=dx/xarctan
原式y=sinx^2+2xdy/dx=2x·cosx^2+2
要是对dy/d(x^2)这形式不习惯,可以令t=x^2,那么函数y=[sin(x^4)]^2就变为：y=[sin(t^2)]^2同时求dy/d(x^2)也就是相当于求：dy/dt了,根据复合函数的求导
dy/d(x^3)=(dy/dx)/(d(x^3)/dx)=cosx/3(x^2)