x2 2xy-10x=0

牛顿迭代法的思想是这样的:x和x0不断的迭代.令f(x)=5*x^5-8x^3+10x^2-7*x+25则f'(x)=25x^4-24x^2+20x-7有:x=x0-f(x)/f'(x)收敛于:|x-

按费拉里公式,原方程可拆分为两个方程2x²+.55405383961193x+9.0521839270015=02x²-4.55405383961193x+2.2094115808

好吧题目应该是x^2+6x+y^2+4y+10=0解体是配方了把10分成1+9配成（x+3）^2+（y+1）^2=0平方大于等于0所以x+3=0,y+1=0,嗯x+y=-4了,希望可以帮到你.

x三次方+3x²-10x=X(X^2+3X-10)=X(X+5)(X-2)=0X1=0X2=-5X3=2

x^2+2x-1=0,x^2+2x=15x^2+10x-3=5(x^2+2x)-3=5*1-3=2

无解,△=25-40

今天才收到这个消息)1、Δ=(-5)²-4×1×(-10)=65X=(5±√65)/2,X1=(5+√65)/2,X2=(5-√65)/2,2、Δ=19-8=41,X=(-7±√41)/4,

 再问：第一次，抄这样的作业再问：好牛逼啊！再答：抄？？？？？你不早说再问：你随便做？再答：啊！说清楚点

f(x)=(2x^2+7x+10)/x=2x+(10/x)+7由于x>0根据均值不等式,有f(x)=2x+(10/x)+7>=7+2√(2x)√(10/x)=7+2√20=7+4√5,当2x=10/x

5(x+y)-2x=03x+5y=06x+10y=0①3x-10(x+y)=27x+10y=-2②②-①x=-2代入①y=6/5

2(x²-7x)²-21(x²-7x)+10=0[2(x²-7x)-1][(x²-7x)-10]=0(2x²-14x-1)(x-5)(x+2

(x^2+5x)^2+10x^2+50x+24=0(x^2+5x)^2+10(x^2+5x)+24=0设(x^2+5x)=y即y^2+10y+24=0(y+4)(y+6)=0y1=-4,y2=-6x^

(x+6)/(x+1)-(3x²+10x+4)/(x²+3x+2)+(2x+1)/(x+2)=0(x+6)/(x+1)-(3x²+10x+4)/(x+1)(x+2)+(2

1/x+1/x(x+1)+1/(x+1)(x+2)+1/(x+2)(x+3)+...1/(x+9)(x+10)=01/x+1/x-1/(x+1)+1/(x+1)-1/(x+2)+1/(x+2)-1/(

就是求根公式,要用根的判别式方程ax²+bx+c=0,则：根=【（-b）±√（b²-4ac）】÷2a像：x²+3x-2=0△=b²-4ac=3²-4×

X²+10X+16=0(x+2)*(x+8)=0x=-2;x=-8

已知函数f(x)=x+1,x≤0,　　　　　=-2x,x＞0,若f(x)=10,则应是　　　x+1=10(x≤0),或-2x=10(x＞0),得知　　　x=9>0(x≤0),或x=-5

x-x²+6=0x²-x-6=0(x+2)(x-3)=0x1=-2,x2=3x²+x-6=0(x+3)(x-2)=0x1=-3,x2=2-x²-3x+10=0x

x^4+2x^3-18x^2-10x+25=0x^4-x^3+3x^3-3x^2-15x^2+15x-25x+25=0(x-1)(x^3+3x^2-15x-25)=0(x-1)(x^3+5x^2-2x

3x²=10x+83x²-10x-8=0x=(10±√(100+4×3×8)/2*3x=(10±√196)/6x=(10±14)/6∴x1=4x2=-2/33x²-10x