（2x-1）2=9（1-2x）怎么解

x到底等于-21/4（-4x²+2x-8）-（1/2x-1）还是等于1/2[补充一下：9x+6x²-3（x-2/3x²）化简得：6x+8x²]再问：x等于-2再

是这样的：x^5+x^4=x^3(x^2+x)=(x^2+x)[(x^3-1)+1]=(x^2+x)(x^3-1)+x^2+x=[x(x+1)(x-1)](x^2+x+1)+x^2+x=(x^3-x)

1）（x-3）/（x-2）-（x-5）/（x-4）=（x-7）/（x-6）-（x-9）/（x-8）化简得【（x-3）（x-4）-（x-5）/（x-2）】/【（x-2）（x-4)】=【（x-7）（x-8

X除以（X-2）+（X-9）除以（X-7)=(X+1)除以（X-1）+（X-8)除以（X-6）(x-2+2/x-2)+(x-7-2/x-7)=(x-1+2/x-1)+(x-6-2/x-6)1+(2/x

[x-x/(x+1)][(x+1)/(x^2+4x+4)][(x^2-4)/(x^2-2x)]=[x^2/(x+1)][(x+1)/(x+2)^2][(x+2)(x-2)/x(x-2)]=x/(x+2

原式=[(x-1)(3x²+9x+7)-(x+1)(2x²-4x+3)-(x³+x+1)]/(x²-1)=[(3x³+6x²-2x-7)-(

由于【（x+1）-x】/x(x+1)=1/x(x+1)所以1/x(x+1)=1/x-1/(x+1)同理可得：1/(x+1)(x+2)=1/(x+1)-1/(x+2)·····所以原方程可写为：【1/x

[(x+2)+1]/(x+2)-[(x+1)+1]/(x+1)=[(x+4)+1]/(x+4)-[(x+3)+1]/(x+3)1+1/(x+2)-1-1/(x+1)=1+1/(x+4)-1-1/(x+

(x^2+9x)(x^2+9x+18)=68040(x^2+9x)^2+18(x^2+9x)+81=68040+81(x^2+9x+9)^2=261^2x^2+9x+9=2614x^2+36x+36+

两边同时乘以2x(x+1)约分后为2(x-1)(x+1)-2x(1-x)=5x(x-1)化简为2x^2-2-2x+2x^2=5x^2-5xx^2-3x+2=0(x-1)(x-2)=0解得x=1或2

[(x^2)^2-2x^2*x+x^2]-(2x^2+2x+1)=0即(x^2-x)^2-(2x^2-2x)-4x+1=0[(x(x-1))^2-2(x(x-1))+1]-4x=0(x(x-1)-1)

1/x（x+1）+1/（x+1）（x+2）+...+1/(x+8)(x+9)=(1/x-1/x+1)+(1/x+1-1/x+2)+...+(1/x+8-1/x+9)=1/x-1/x+9=9/x(x+9

x(x^2-1)+2x^2*(x+1）-3x*(2x-5)=x(3x^2-4x)-28;x^3-x+2x^3+2x^2-6x^2+15x=3x^3-4x^2-28;14x=-28.x=-2.

(x-1)^3(x+1)（x-2）/(x+4)

题目太多了请分开求助,我好多赚点采纳数哈:)多谢啦4×（0.8-x）=1.40.8-x=1.4÷4=0.35x=0.8-0.35=0.455+2/3x-1/2x=12(2/3x-1/2x)=12-5(

看来是因式分解题目（x+1)(x+2)(x+3)(x+4）+1=(x+1)(x+4)(x+2)(x+3)+1=(x^2+5x+4)(x^2+5x+6)+1=(x^2+5x)^2+10(x^2+5x)+

你题目里面M应该抄错了,应该是(X²+2X+1）（X²-2X+1）M-N=(X²+2X+1）（X²-2X+1）-（X²+X+1）（x²-X+

（x+2/x^2-2x-x-1/x^2-4x+4）/x-4/x=[(x+2)/x(x-2)-(x-1)/(x-2)²]／(x-4)/x=[(x²-4-x²+x)/x(x-

=4*（-27）+64=-44

方程右边的1减到左边来,再同分得到（6x-2)/(x^2-x)=0得到x=1/3这个方程即使两边乘以x^2-x,x的最高次数为2次,也不会出现x^3,你肯定是什么地方弄错了