计算圆面积 提供4个输入框,输入4个值,然后在浏览器输出面积.

#include <stdio.h>#include <math.h>//输入三个点void inputThreePoint(double&nbs

PrivateSubCommand1_Click()IfNotIsNumeric(Trim(Text1.Text))ThenMsgBox"A不是数字"Text1.SetFocusExitSubEndI

#include#definePI3.1415926\x05\x05voidmain()\x05{\x05doubler,s;scanf("%f",&r);s=PI*r*r;\x05printf("A

programsample;vari,x,s,q:longint;begins:=0;q:=0;fori:=1to30dobeginread(x);inc(s,x);inc(q,sqr(x));end

PublicSubcommand1_click()dimrasintegerr=val(inputbox("请输入半径"))s=3.1415926*r^2msgbox"圆的面积为:"&sendsu

#includevoidmain(){floatr,d,Cs;cout

PrivateSubCommand1_Click()DimbjAsSingleDimzzAsSingleDimmjAsSinglebj=CSng(Text1.Text)Ifbj

#include<stdio.h>void main(){    int sum=0;   &nb

#include#include#defineP3.14doublearea(doubler){returnP*r*r;}doubleCircumference(doubler){return2*P*

#include#definepai3.15149256voidmain(){doubler,c,s;printf("pleaseinputr\n")scanf("%lf",&r);printf("c

答案是C.输入10000个数值,计算平均数,适合采用循环结构算法.A.判断一个证书是否为偶数,解决该问题仅需一步判断,也许需要一步赋值,没有多次重复的步骤,不适合采用循环结构算法.B.输入一个圆的半径

ConstPI=3.14159DimrAsDoubleDimCAsDoubleDimSAsDoubleIfIsNumeric(Text1.Text)Thenr=Val(Text1.Text)C=2*P

他们的答案好像都没有输出结果.Dim r, s, c As IntegerPrivate Sub Command1_Click()

PublicFunctionArea(aAsDouble,bAsDouble,cAsDouble)AsDoubleIfa+bMSGBOX"要求任意两边之和大于第三边"ExitFunctionendif

#includeclasscircle{private:intr;public:voidinput(){cout

#includeintfact(intn){intt=1;for(inti=1;i

importjava.util.*;publicclassPrintDemo{publicPrintDemo(){System.out.println("请选择您的要求,输入要求编号按回车键");Sy

建立一个text1、一个command1,代码如下：PrivateSubCommand1_Click()IfNotIsNumeric(Text1.Text)ThenMsgBox("请先在框中输入数字的

每伏匝数应用公式ωo=45/S=45/3.9X3.5=45/13.65=3.3匝输入线圈匝数ω1=3.3X220=726匝

我不会啊啊