解方程:x的三次方减3x的平方+4＝0-搜答案-拍题作业网

（x+y)^2=x^3+y^3(x+y)^2=(x+y)(x^2-xy+xy^2)x+y=x^2-xy+y^2x^2-(y+1)x+y^2-y=0判别式=(y+1)^2-4(y^2-y)=y^2+2y

x³+3x²+3x-7=0x³-x²+4x²+3x-7=0x²(x-1)+(x-1)(4x+7)=0(x-1)(x²+4x+7)=

6.联立a-b=30,b-c=25,两式相加,得a-c=55,a方-b方=1650可拆分成（a+c)(a-c)=1650,除以前面得出来的就是a+c=305.既然无意义,说明y-5为0,就是y为5,x

3a-12a³=3a(1-4a²)=3a(1+2a)(1-2a)(x-3)²-12a³=~是否写错了?

3x的三次方-[x的三次方+（6x的平方-7x)]-2(x的三次方-3x的平方-4x)=3x³-x³-6x²+7x+2x³-6x²-8x=4x

x³-y³+x²y-xy²=32(x-y)(x²+xy+y²)+xy(x-y)=32(x²+2xy+y²)(x-y)=3

题目是-x^3+3x^2-3x+5=0吗?核对一下有没有弄错的再问：其实题目是1/(x-2)+1/(x-1)=x-2/(1-x)再答：貌似你给的式子化不过去啊，还有，小月满满已经把你那个3次方的解决了

解一元三次方程其实也是有公式的.X-3X-4=0方程为:y^3+py+q=0的结构.设y=u+vp=—3uv则（u^3+v^3)+3uv(u+v)+p(u+v)+q=0=>u^3+v^3+q=0所以q

x³-3=3/8x³=3+3/8x³=27/8x=3/2很高兴为您解答,【the1990】团队为您答题.请点击下面的【选为满意回答】按钮.

x(x-1)(x-2)³(x+1)(x-1)(x-1)(x²+x+1)/[(3-4x)(x²+x+2)]>0x(x-1)³(x-2)³(x+1)(x&

X(X+1)~2=1,——（X+1）~2=1/X——函数Y=（X+1）~2和函数Y=1/X在第一象限有一个交点,所以方程x三次方+2x平方+x-1=0的实根的个数有1个.

（x+2）（x²-2x）=x³-8x(x+2)(x-2)-(x-2)(x²+2x+4)=0(x-2)(x²+2x-x²-2x-4)=0x-2=0x=2

x^3-2x^2+1=0(x^3-1)-2(x^2-1)=0(x-1)(x^2+x+1)-(x-1)(2x+2)=0(x-1)(x^2-x-1)=0x1=1x2=(1+根号5)/2x3=(1-根号5)

x⁴+x³+4x²+3x+3=x⁴+x³+x²+3x²+3x+3=x²(x²+x+1)+3(x²

a^3x^2+a^2x-2ax-2=0a^2x(ax+1)-2(ax+1)=0(a^2x-2)(ax+1)=0x1=2/a^2x2=-1/a

x^3=27/8x=3/2

1、x(x²-5x+6)=0x(x-2)(x-3)=0∴x=0x=2x=32、两边乘以3x(x-1)得3(x-1)²+3x²=10x(x-1)3x²-6x+3+

x³-y³-x²y+xy²=(x³-y³)-(x²y-xy²)=(x-y)(x²+xy+y²)-xy

x三次方+x平方-5x+3=0x^3+x^2-2x-(3x-3)=0x(x^2+x-2)-3(x-1)=0x(x+2)(x-1)-3(x-1)=0(x-1)(x^2+2x-3)=0(x-1)(x+3)

x(x^2-1)=0解出x=-1、0、1