解方程:x-2分之1减去x的2次方减4分之4=1
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再问:不对吧再问:减四变加四再答:笔误再问:好像还有一处不对再问:x+1成x+1再问:是不是等于x的平方加2x+2再问:不对,是最后加一再答:那没错再问:最后加一不是加二吧再答:对再答:因
1/2-x/3=1-x/3=1/2-x=3/2x=-3/2
去分母得:(X-1)(X+1)-(X-2)^2=2X+a,2X=a+5,X=(a+5)/2根据题意得:(a+5)/2
①x-2分之1-x=2-x分之1-21-x=-1-2x+4x=2②x+2分之2x减去x-2分之x=1+4-x的平方分之x+112x(x-2)-x(x+2)=x²-4-(x+11)2x
能把题目说的更明白点么?
你表达的方程的意思是不是x/(x-2)-1=1/(x²-4)那么等式两边同时乘以x²-4,得到x*(x+2)-x²+4=1于是2x=-3解得x=-3/2
把x移到一边3分之2减3等于8x减2分之1x-7/3=15x/2x=-14/45
去分母:(x-1)^2-x(x+2)=m去括号:x^2-2x+1-x^2-2x=m4x=1-mx=(1-m)/4解为负值,所以(1-m)/4<0,解得:m>1另外负值中应排除增根-2,所以(1-m)/
x+1分之x+2减去x+3分之x+4=x+5分之x+6减去X+7分之x+8方程两边分别通分,得[(x+2)(x+3)-(x+1)(x+4)]/[(x+1)(x+3)]=[(x+6)(x+7)-(x+8
你要说的是:(x+2)分之(x+1)减去(x+3)分之(x+2)等于(x+7)分之1减去(x+6)分之1解方程(x+1)/(x+2)-(x+2)/(x+3)=1/(x+7)-1/(x+6)通分得[(x
解分式方程输入很辛苦.经检验X=7/2是原方程的解.
x分之2减去x+1分之x=1两边同乘以x(x+1),得2(x+1)-x²=x(x+1)2x²-x-2=0
(X-3)/X=2/3X-8/3解得x=1
x/(x+3)-(x+1)/(x-2)=(x-2m)/(x^2+x-6)x/(x+3)-(x+1)/(x-2)=(x-2m)/[(x-2)(x+3)]同时乘以(x-2)(x+3),得x(x-2)-(x
由(x-1)/(x+2)-x/(x-1)=m/(x+2)(x-1),左边通分:[(x-1)²-x(x+2)]/(x+2)(x-1)=m/(x+2)(x-1),比较两边分子:-4x+1=m,-
直接移就行0.7分之x-1.4x=1+0.3分之1.70.7分之0.4x=0.3分之20.7乘以2=0.4x乘以0.30.12x=0.146x=7
(x-1)(x-3)(x-4)(x-5)-(x-1)(x-2)(x-3)(x-5)=(x-1)(x-2)(x-4)(x-5)-(x-1)(x-2)(x-3)(x-4)(x-1)(x-3)(x-5)(x
x/(x+2)-(x+2)/(x-2)=8/(x^2-4)x(x-2)-(x+2)^2=8x^2-2x-x^2-4x-4=8-6x=12x=-2
x+4=3x=7
X^2/X-2-X/X-2-1+X/2-XX^2-X/X-2-1+X/2-XX^2-X/X-2+1+X/X-2X^2-1/X-2这么简单的题咋能用此乃的口吻~?比我还悲伤