编写一个程序,计算两个5*5矩阵相加

#includevoidmain(){inta,b;printf("Inputtwointegers:");scanf("%d%d",&a,&b);printf("和:a+b=%d\n",a+b);p

privatesubform_click()dimnaslong,snaslongn=inputbox("请输入n")fori=0tonsn=sn+2*i+1nextmsgbox"1+3+5+...(

//别说100位,1000位都没问题,给你个例子.#include#definePRECISION2800#defineFRACTION1000#defineGROUP4#defineINITIALV

PrivateSubCommand1_Click()Dima,xAsSinglea=Val(Text1.Text)Ifa再问：x=x+a*0.2+3000*0.2怎么都乘0.2呀？

#includeintmain(){intm,n;do{printf("输入两个非零整数:\n");scanf("%d%d",&m,&n);}while(m==0||n==0);printf("%d+

INPUT"a=",aINPUT"b=",bPRINT"|a|+|b|=";abs(a)+abs(b)#includeinta,b;scanf("%d",&a);scanf("%d",&b);prin

VB程序PrivateSubCommand1_Click()Dima,iAsIntegeri=1Whilei<50s=s+(i+1)/ii=i+1WendPrint"s=";sEndSu

#includeintfact(intn){if(n==0||n==1)return1;elsereturnn*fact(n-1);}intmain(){printf("5!+10!=%d\n"

#includevoidmain(){floata,b,result;charc;printf("pleaseinputastatement:");scanf("%f%c%f",&a,&c,&b);s

#include#includevoidmain(){intsum,i;sum=0;for(i=1;i

voidGetGCMAndLCM(inta,intb,int*iGCM,int*iLCM){intiMin=a>b?b:a;intiMax=(ainti=1;intiMaxIndex=0;

程序框图如下：程序如下：s=1i=3DOs=s*ii=i+2LOOPUNTILi＞99PRINTsEND

#include <stdio.h>int main(){  float x, tax = 0; 

publicclassTest{publicstaticvoidmain(String[]args){ints=0;intn=1;for(inti=0;i

publicclassTestArray{publicstaticvoidmain(String[]args){intm=0;for(inti=1;iintn=1;for(intj=1;jn=n*j;

doublefunction(intn){doublevalue=0;for(inti=1;i

;MOVAX,AANDAX,B;AX=aANDbMOVBX,AXORBX,B;BX=aXORbADDAX,BXADDAX,BX;AX=2*(aXORb)+aANDbADDAX,A;AX=a+2*(aX

#includeintmain(){intsum=0;inti=1;intj=1;for(;i

"计算两个给定的长方形的周长和面积"是两个长方形还是一个长方形..需要输入什么条件..如果是输入长,宽,然后计算面积的话..那么#include"stdio.h"voidmain(){floatcha

#includevoidmain(){inta,b,d;charc;printf("请输入一种运算符：\n");scanf("%c",&c);printf("请输入两个数：\n");scanf("%d